# PMC Logical Reasoning Question – Letter And Symbol Series Questions

## Solved Example – Number Series

**Question 1.**20, 32, 45, 59, 74, ?

(B) 90

(C) 85

(D) 79

**Solution:**

**The differences between consecutive terms of series**

**Question 2.**210, 195, 175, 150, 120, ?

(B) 80

(C) 85

(D) 90

**Solution:**

**Question 3.**3, 5, 10, 12, 24, 26, ?

(B) 30

(C) 28

(D) 48

**Solution:**

5th term = 2×4th term

**Question 5.**2, 6, 10; 5, 9, 13; 10, 14, 18; ?, ?, ?.

(B) 14, 17, 20

(C) 17, 21, 25

(D) 15, 20, 25

**Solution:**There is a common difference of 4 among consecutive terms

Thus, ?, ?, ? = ( 10 + 7), (17 + 4), (21 + 4)

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## Solved Example – Wrong Number

**Question 1.** 1, 11, 26, 49, 80, 122, 169, 227, 290, 361

(A) 49

(B) 26

(C) 80

(D) 122

The answer is (C).

**Solution:**

The differences between the consecutive terms of series are

5, 8, 11; 5, 8, 11; ………

2nd term = 1st term + 10 = 1 + 10 = 11

3rd term = 2nd term + 10 + 5 = 11 + 10 + 5 = 26

4th term = 3rd term + 10 + 5 + 8 = 26 + 10 + 5 + 8 = 49

5th term = 4th term + 10 + 5 + 8 + 11 = 49 + 10 + 5 + 8 + 11 = 83

Thus, fifth term should be 83 and not 80.

**Question 2.** 11, 5, 20, 12, 40, 26, 74, 54

(A) 5

(B) 20

(C) 26

(D) 40

**Solution:**

The differences between odd terms are 9, 18, 36, ……….

3rd term = 1st term + 9 = 11 + 9 = 20

5th term = 3rd term + 18 = 20 + 18 = 38

7th term = 5th term + 36 = 38 + 36 = 74

Thus, 5th term should be 38 and not 40.

The answer is (D).

**Question 3.** 3, 6, 5, 20, 7, 42, 9, 74

(A) 6

(B) 42

(C) 74

(D) 20

The answer is (C).

**Solution:**

Differences between the even terms of the series are 14, 22, 30……

4th term = 2nd term + 14 = 6 + 14 = 20

6th term = 4th term + 22 = 20 + 22 = 42

8th term = 6th term + 30 = 42 + 30 = 72

Thus, 8th term should be 72 and not 74.

## Solved Example – Alphabet Series

**Question 1.**ABXW, EFTS, ?, MNLK

(A) IJOP

(B) IJPO

(C) JIOP

(D) JIPO

The answer is (B).

Solution

The first and second terms are in alphabetic sequence , while third and fourth are in reverse sequence. Therefore, missing item is IJPO.

**Question 2.** A Z X B V T C R ?

(A) E, O

(B) O, Q

(C) F, O

(D) P, D

The answer is (D).

**Solution:**

The 1st, 4th and 7th letters are in alphabetical order.Therefore, 10th letter will be after C i-e D. Also 2nd and 3rd letter are in reverse order and so are the 5th and 6th letters.

**Question 3.** P3C, R5F, T8I, VI2, L, ?

(A) YI7O

(B) XI7M

(C) XI7O

(D) XI6O

The answer is (D).

**Solution:** The 1st letter of the terms are alternating. And the sequences are followed by the numbers is +2, +3, +4 …The last letter of each term are moved 3 steps forward to the last letter, so, ? = XI7O

**Question 4.** AK, EO, IS, ? , QA, UE

(A) LV

(B) MW

(C) NX

(D) LW

(E) MV

The answer is (B).

Solution:

so here

From A in 1st term to E in 2nd term , count A to E then E will be on 4th number , similarly from E to I , I is also on 4th number , now count from I to next 4th number that is M so in this ? term first letter will be M

Now move to 2nd number of terms In first term 2nd number is K now count from K to O , O is on 3 number count , now after next 3rd count their is S, next 3rd count will be W so W will be the 2nd digit of ? term.

Excellent

thanks for feedback

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